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the drama club sold 1500 tickets for the end of -year performance. admission . prices were $12 for adults and $6 for students. the total amount collected at the box office was $15600 . how many students attended the play?
thanx

2006-11-26 06:29:56 · 7 answers · asked by pearl 2 in Science & Mathematics Mathematics

7 answers

let

x = Students

y = Adults

1500 = Total tickets

6x = price for students

12y = price for adults

15600 = Total collected

- - - - - - - - - - - - - - - - -

x + y = 1500- - - - - - - Equation 1
6x + 12y = 15600- - - -Equatioh 2

- - - - - - - - - - - --

Substitute Method equation 1

x + y = 1500

x + y - x = 1500 - x

y = 1500 - x

Insert the y value into equation 2

- - - - - - - - - - - - - - - - - - - - - - -

6x + 12y = 15600

6x + 12(1500 - x) = 15600

6x + 18000 - 12x = 15600

- 6x + 18000 - 18000 = 15600 - 18000

- 6x = - 2400

- 6x/-6 = - 2400/- 6

x = 400

The answer is x = 400

Insert the x value into equation 1

- - - - - - - - - - - - - - - - - - - - - - -

Solving for y

x + y - 1500

400 + y = 1500

400 + y - 400 = 1500 - 400

y = 1100

The answer is y = 1100

Insert the y value into equation 1

- - - - - - - - - - - - - - - - - - - - - -

Check for equation 1

x + y = 1500

400 + 1100 = 1500

1500 = 1500

- - - - - - - - - - -

Check for equation 2

6x + 12x = 15600

6(400) + 12(1100) = 15600

2400 + 13200 = 15600

15600 = 15600

- - - - - - - - - - -

The solution set is { 400, 1100 }

- - - - - - - s-

2006-11-26 07:12:26 · answer #1 · answered by SAMUEL D 7 · 0 0

# Adult tickets - A
# Student tickets - S

We'll set up equations that we can solve, and we can find a solution because we have two variables and two equations.

A + S = 1500
12A + 6S = 15600

Divide the second one by 6 to get

2A + S = 2600
A + A + S = 2600

We have A + S, which we know equals 1500. Plug that in! We get

A + 1500 = 2600
A = 1100
S = 1500=1100 = 400

400 students.

2006-11-26 06:35:23 · answer #2 · answered by Aegor R 4 · 0 0

X=adults
1500-X=students
12X+6(1500-X)=15600
12X+9000-6X=15600
6X=6600
X=1100 (adults)
1500-X=
1500-1100=400 (students)

2006-11-26 06:39:45 · answer #3 · answered by Joseph F 5 · 0 0

A+S=1500
12A+6S=15600
dividing by -6
-2A-S=-2600
adding to (1)
-A=-1100
A=1100
sub S=400
so 1100 adults and 400 students

2006-11-26 06:34:27 · answer #4 · answered by raj 7 · 0 0

12x + 6y = 15,600
x + y = 1500

x = 1500 - y

12 (1500-y) + 6y = 15,600
18,000 - 12y + 6y = 15,600
18,000 - 15,600 = 12y - 6y
2,400 = 6y
400 = y

x + y = 1500
x + 400 = 1500
x = 1100

Check~
so:
12x + 6y = 15,600
12 ( 1100) + 6 ( 400) = 15,600
13,200 + 2,400 = 15,600
15,600 = 15,600

x + y = 1500
(1100) + (400) = 1500
1500 = 1500

1500 students total.

2006-11-26 06:52:52 · answer #5 · answered by Dee_Smithers 4 · 0 0

a+c=1500
12a+6c=15600

a=1500-c

12(1500-c)+6c=15600
18000-12c+6c=15600
-6c= -2400
c= 400

a+c=1500
a+400=1500
a=1100

there are 1100 adults and 400 children

2006-11-26 06:37:10 · answer #6 · answered by      7 · 0 0

first one, minus 0.9 from itself and from -a million.5 youll get 0.8x= ____ <-the version of -a million.5-0.9 then divide by 0.8 from the two factors to cancel out the 0.8 x= even though the version of -a million.5-0.9 / 0.8 2d one.. 6(x) = 6x+ 6(a million.37)=5x .. 6x+7.37=5x minus 6 x from the two factors 7.37=-x divide by -1x on the two factors x=-7.37

2016-10-04 09:35:35 · answer #7 · answered by ? 4 · 0 0

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