Write the equation using the function notation.?

Question

Find an equation of the line through the point (2,5) that is perpendicular to the line y = 1/2x + 6.

Is it F(x) = -2x + 1 ?

Answer 1

m= -2
y=mx+b
5= -2(2)+b
5= -4+b
b=9
y= -2x+9

Answer 2

confident, the equation is interior the type f(x) =. In function notation, f(x) takes the situation of y. besides the undeniable fact that, the slope of the line is (y1-y2)/(x1-x2) = (9-(-a million))/(-2-3) = 10/-5 = -2, no longer 2. consequently, the equation we've is f(x) = -2x + b. Plug in 3,-a million for x and f(x) respectively, and x is 5. So the equation is f(x) = -2x + 5

Answer 3

answer to your question is no. using a common straight line equation of y=Mx+B. a line perpendicular to 1/2x+6 must have a negative reciprocal slope, in this case M=-2. to find the y intercept or B substitute the point coordinates in y=-2x+B. then
5=-2(2)+B so that B=9. so your new line is y=-2x+9.

hold the applause.

Answer 4

Perpendicular means that the slopes, when multiplied together, make -1. Thus, divide the slope you have by -1. A trick is to flip it and reverse the sign - taking the "negative reciprocal."

Your slope will be -2.

5 = -2(2) + b
b=9

F(x) = -2x + 9

Be careful that you make sure the point is (2,5) not (-2,5). Your function would work if it were the latter.

Answer 5

OK for a line to be perpendicular to another the coefficients for the variable x have to be the opposite inverse like you have shown. then knowing the x and y coordinates from the point and the coefficient of x simply solve for the shift value. but the shift should be 9 so it should be -2x+9.

Answer 6

perpendicular to y=1/2x+6
so slope of the required line=-2
equation
y-5==-2(x-2)
y-5=-2x+4
2x+y-9=0
y=-2x+9
f(x)=-2x+9