can anyone help me with this ellipse problem...
the eqn. of an ellipse is (x-3)^2 / 25 + (y+2)^2 / 169 =1
what are the lengths of the major and minor axes and the distance b/w the foci? and what are the coordinates of the focal points??
2006-11-26 05:05:30 · 3 answers · asked by Jenn 1 in Science & Mathematics ➔ Mathematics
(x-3)² / 25 + (y+2)² / 169 = 1
ie (x-3)² / 5² + (y+2)² / 13² = 1
Thus centre ≡ (3, -2)
Length of semi-major axis (a) = 13 on vertical axis
Length of semi-minor axis (b) = 5 on horizontal axis
Eccentricity (e) = √(1 - (b/a)²)
= √(1 - (5/13)²)
= 12/13
Focal length = ea
= 12/13 * 13
= 12
So distance between the foci = 24
Thus focus 1 ≡(3, -2+ 12) ≡(3, 10)
and focus 2 ≡(3, -2 - 12) ≡(3, -14)
2006-11-26 05:39:19 · answer #1 · answered by Wal C 6 · 0⤊ 0⤋
(7,2) (4,9)
now you better find how i got that b4 your next maths exam
2006-11-26 13:13:22 · answer #2 · answered by Twista-Adzy 2 · 0⤊ 1⤋
real comlicated gal
2006-11-26 13:10:04 · answer #3 · answered by n nitant 3 · 0⤊ 1⤋