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Given the following rational function:

f(x)= 2x^3-1 / x^2-16

Find equations for the horizontal or oblique asymptotes if any.

2006-11-26 05:02:58 · 2 answers · asked by love_never_wanted_me 1 in Science & Mathematics Mathematics

2 answers

As x becomes infinitely large in either the positive or negative direction, f(x) approaches the line y = 2x because the constant terms are negligible compared to the x^3 and x^2 terms, so the ratio 2x^3 / x^2 = 2x dominates. There is no horizontal asymptote, but there are vertical asymptotes at x = 4 and x = -4 because the denominator has roots there.

2006-11-26 05:06:20 · answer #1 · answered by DavidK93 7 · 0 0

Factor the denom: (x-4)(x+4); so there are two vertical asymptotes at x= +-4. An interesting function

2006-11-26 13:11:42 · answer #2 · answered by kellenraid 6 · 0 0

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