2006-11-26 04:47:18 · 8 answers · asked by DEBRA S 1 in Science & Mathematics ➔ Mathematics
The slope of y=2/3x - 4 is....?
2/3 right.
The slope of a line that is perpendicular to that would be....?
The negative reciprocal of 2/3, which is -3/2, right.
So if you have the slope of -3/2 and the y-intercept of 3, the equation would be....?
y = mx + b = -3/2 x + 3, very good.
2006-11-26 04:51:05 · answer #1 · answered by Jim Burnell 6 · 0⤊ 0⤋
When two lines are perpendicular, their slopes will be the negative reciprocals of each other.
The slope of a line perpendicular to y=(2/3)x - 4 would be -(3/2)
You are give the y-intercept of (0,3). The slope-intercept form of a line is y = mx + b. You have the m, x, and y values. Plug them in and solve for b.
3 = -(3/2)(0) + b
b = 3
The equation of the perpendicular line is y = -(3/2)x + 3.
Hope that helped.
2006-11-26 12:56:51 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Given information
Perpendicular to slope 2/3 is slope -3/2 (negative reciprocal)
Y-intercept is 3
Solution
y = -(3/2)(x)+3
2006-11-26 13:34:52 · answer #3 · answered by Anonymous · 0⤊ 0⤋
the given line hasa slope of 2/3
slope of the perpendicular line=-3/2
equation
y=(-3/2)x+3
2006-11-26 12:49:47 · answer #4 · answered by raj 7 · 0⤊ 0⤋
the slope of the line is given by slope(1)*slope(2)=-1
slope 1 = 2/3 so slope 2 =-3/2
the equation is -3/2x + 3
2006-11-26 12:57:00 · answer #5 · answered by maussy 7 · 0⤊ 0⤋
aplly y=mx+c
c= 3
m * m' = -1
m'= 2/3
hence m= -3/2
hence eqation is y= -3/2x+3
2006-11-26 12:51:52 · answer #6 · answered by n nitant 3 · 0⤊ 0⤋
m(1)m(2)=-1
2/3x(-3/2)=-1
therefore m=-3/2
y=mx+b
since b=3
y=-3/2+3
2006-11-26 12:59:08 · answer #7 · answered by arumisan 2 · 0⤊ 0⤋
y= -3/2x+3
2006-11-26 12:49:05 · answer #8 · answered by 7 · 0⤊ 0⤋