173.7
uhhhh...yeah what he said ...thats what i meant!!!!!...LOL
2006-11-26 04:49:06
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answer #1
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answered by Raizedbywolves 2
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Use cosine rule of triangle. let C be the dist between 2 transmitter then c(pow of 2)=70*70+130*130-2*70*130*cosine(117.4).Square root of c will give u the answer
2006-11-26 16:21:50
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answer #2
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answered by rex n 1
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The Law of Cosines
For a triangle with sides a,b, and c and the angle µ opposite the side c, one has
c2 = a2 + b2 - 2ab·cos(µ)
Use this law of cosine. Where C is the distance between the transmitters.
2006-11-26 12:49:53
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answer #3
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answered by eric l 6
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use scale of 1cm=40 miles.
draw a line of 130 miles(use the scale) as ur base line. At 1 end point draw an angleof 117.4. The line should be70 miles(use scale).
Form a triangle out of it. Find the length of the 3rd line u drew.
2006-11-26 14:43:44
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answer #4
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answered by Anonymous
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not positive yar but i THINK it is
.3044444444 times 147.6482306= about 50
* Don't ask where I got the first two numbers from.
*Dude, you taking geometry, wow that was hard!
2006-11-26 13:02:35
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answer #5
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answered by Anonymous
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they are 100 miles away from each other
2006-11-26 12:42:47
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answer #6
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answered by I love HBK 2
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ya, use the law of cosines
2006-11-26 12:52:21
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answer #7
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answered by Guess who? 2
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maths are of history.
to me it's a mystry.
2006-11-30 09:56:03
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answer #8
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answered by mirchi girl 3
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math
2006-11-26 12:42:27
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answer #9
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answered by Anonymous
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maths ?
-jindajind ?
2006-11-26 12:47:09
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answer #10
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answered by Anonymous
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