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Problem is x(squared) + 9x + 5 = 0

Choices for answer:

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2
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2006-11-26 04:20:23 · 5 answers · asked by tia 3 in Science & Mathematics Mathematics

5 answers

check the discriminant:
81-4(5) = 81 -20 =61 >0,
so there are 2 real solutions to this problem
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2006-11-26 04:22:35 · answer #1 · answered by Anonymous · 1 0

1

2006-11-26 04:40:12 · answer #2 · answered by ide_egbe 1 · 0 0

x^2+9x+5=0
using the quadratic function
x=-9 plus or minus the square root of (9^2-4x1x5) all divided by 2x1
=-9 plus or mins the square root of 61, all over 2
therefore there are two solutions:
-9 plus the square root of 61, all over 2
=-9 mins the square root of 61, all over 2
if you are talking about real solutions, then there is none since the square root of 61 is complex number (is the term complex right)

2006-11-26 05:09:49 · answer #3 · answered by arumisan 2 · 0 0

2 solution it means that this parabolic eqation will intersecting x axis on two pts
cuz
discriminant (b*b -4ac)^2 = having solution

2006-11-26 04:57:36 · answer #4 · answered by n nitant 3 · 0 0

any second degree equation will have 2 solutions
here both will be real solutions but irrational

2006-11-26 04:22:55 · answer #5 · answered by raj 7 · 0 1

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