The balanced chemical equation and the molecular weights of the reactants and products.
In simplest form, assume
XY + AB = XB + AY.
Assume the molecular weight of XY is 50, and of XB 35.
For every 50 grams (or pounds, tons, or any other measure of mass) of XY you use, you will get 35 grams (or whatever) of XB.
EDIT:
OK. Atomic weights are H=1, S=32, Cl=35.5, Fe=56. Molecular weights are FeS=88, HCl=36.5, H2S=34, FeCl2=127.One gram molecular weight of each is its molecular weight in grams. So if you react 88 grams of FeS with 36.5 x 2 grams of HCl (the balanced equation tells you that you need 2 moles of HCl, so you multiply by 2), you will get 34 grams of H2S and 127 grams of FeCl2.
Notice that the weights balance. You put in 88 + (36.5 X 2) grams, or 161 grams. You got out 127 + 34, or 161 grams.
You need the mass of any one of those compounds - either reactant or product - to determine all the others. Calculate the moles of the one for which you have the mass, determine the ratio of the moles of that one to the others, multiply by that ratio and then multiply result by molecular weight.
2006-11-26 03:54:13
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answer #1
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answered by dollhaus 7
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There is no good general answer to this question. We definitely need to know WHAT reaction but then things get complicated. The mass of the individual reactants would tell us or the mass of the products. That said there are lots and lots of other ways to figure it out based on determination of the (extensive) (extrinsic) properties of the reactants or products. In the ammonia reaction mentioned, the pressure, volume and temperature of the product could be used to determine the masses. Energy given off, amount of light absorbed, pressure change, all sorts of measurements have been used to answer your question in specific cases. For a simple textbook case xA -> yB +zC
you need the molecular (and/or atomic) weight of A, B and C.
Then you need some way to figure out x, y or z. And there are countless ways, depending on what else is known about A, B, or C.
2006-11-26 04:03:35
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answer #2
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answered by Anonymous
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consider the reaction ie formation of ammonia .
N2(g) +3H2(g) ----> 2NH3(g)
u can calculate amount of NH3 by knowing
(i) the amounts of both N2 & H2 reacted
OR
(ii) limiting reagent .
limiting agent is the reactant present in scarcity as compared to the other reactant .
for eg if N2 is the limiting reagent then formation of NH3 will only depend on N2 (not on H2)
2006-11-26 03:49:19
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answer #3
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answered by Anonymous
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one million) c is the only equation using -> 2) a. KOH + HCl _> KCl _ H2O that's balanced b. Pb(NO3)2 + 2KI -> 2KNO3 + PbI2 c. idk this one sorry d. 2NaCl + H2SO4 -> Na2SO4 + 2HCl 3) the subscript in basic terms refers back to the factor its related to not the whole compound and whilst balancing you're balancing all the climate in the compound not in basic terms one factor. 4) the restricting reagent? and how quite some each little thing?? im undecided approximately this one 5)you're able to desire to transform 34g of NH3 to moles of NH3 then use the stoichiometric coefficients from the balanced equation then convert that to grams of N. 34g/17g= 2 mol NH3 2 mol NH3 * one million mol N2/2 mol NH3 = one million mol N2 one million mol N2* 28 g N2 = 28 g N2 desire this facilitates!! :)
2016-12-29 12:30:34
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answer #4
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answered by Anonymous
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