Compare column A with B?

Question

a+bi=(3+i)(4-2i)
c+di=(-2-3i)(3+5i)

Column A: B Column B: D

Choices for answer:

Quantity in A is greater
Quantity in B is greater
They're equal
Cannot be determined

Answer 1

Start by multipying out (3 + i)(4 -2i). This is 12 - 6i - +4i +(-2i*i) which is 12 - 6i - +4i +2, which is 12 -2i + 2 or 14 -2i. You said that equals a -bi, so a is 14 and b is -2.
Similarly (-2 -3i)(3 + 5i) = -6 -10i -9i + 15 = 9 - 19i. This equals C +di, so c = 9 and d = -19.
-2 > -19, so b>d.

Answer 2

I am not sure what you mean by columns, but I will give this a try.
a+bi = (3+i)(4-2i) = 12 -6i +4i -2i^2 = 14 - 2i, so a= 14 and b = -2.

c+di =(-2-3i)(3+5i)=-6-10i-9i-15i^2 =9-19i, so c=9 and d = -19

Now Column A:B and Column B:D can be computed and the answer can be determined. I would do this for you but I do not know what these two columns are. I could only guess that they are columns in some matrix.