2006-11-26 02:39:07 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Astronomy & Space
Light exists in various wavelenghts. You may be referring to the visible component of light, however ther are the non visible (by the naked eye) components such as x-rays, ultraviolet and others. If you look online you will see most pictures of galaxies etc. use both visible and invisible components. So yes, you can produce forms of light in darkness.
2006-11-26 02:44:35 · answer #1 · answered by Fred M 2 · 0⤊ 1⤋
beneficial it rather is. Produce any electromagnetic radiation exterior the seen spectrum and additionally you have black mild. besides the fact that, if by making use of "black" mild you propose some mild source that would have the outcome of black in coloration mixing, then you are maximum suitable. you may not make a mild source which will produce a dark, colorless spot on a until eventually now (in the previous it rather is grew to become on) white floor. reason? there is not any coloration black, that's the absence of seen mild.
2016-12-17 16:30:12 · answer #2 · answered by ? 3 · 0⤊ 0⤋
no . because black refers to darkness . only when light falls on a black body the black color is reflected thatsol. it is impossible to produce a light in black.
2006-11-26 02:44:49 · answer #3 · answered by Anonymous · 0⤊ 0⤋
manickava is wrong becase when light falls onto a black object all the wavelengths are absorbed and not reflected..thats why its black
and no i dont think its possible to get black light..isnt light meant to help us see better?? why would u wana shine darkness on something and u cant see anything????
2006-11-26 02:51:33 · answer #4 · answered by acnemycin 3 · 0⤊ 0⤋
If we borrow from the matter/antimatter theory, I would say that you could have, for lack of a better way to put it, anti-light. Which would have the same but opposite properties than light.
2006-11-26 02:46:06 · answer #5 · answered by bofh772 2 · 0⤊ 0⤋
It's not possible in reality, but it is possible with an optical simulator called a "raytracer". You can define light sources with negative brightness, that are literally "darkbulbs".
2006-11-26 04:07:58 · answer #6 · answered by poorcocoboiboi 6 · 0⤊ 0⤋
Black lights are actually ultraviolet
2006-11-26 03:29:42 · answer #7 · answered by ZeedoT 3 · 0⤊ 0⤋
not possible as black is the absence of light.
what is commomly refered to as black is not "black" but ultraviolet
and is known as black because we cannot see it.
God bless,
gabe
2006-11-26 03:38:00 · answer #8 · answered by gabegm1 4 · 0⤊ 0⤋
No...black is literally the ABSCENCE of light.
2006-11-26 02:40:55 · answer #9 · answered by Anonymous · 0⤊ 0⤋
no....i don't think it is. black is no real thing....it is just the absence of light or coloured light. black is not a colour. it doesnt have any specific wavelength. its just wat wud be left if there was not light source
2006-11-26 04:45:47 · answer #10 · answered by amandac 3 · 0⤊ 0⤋