Second Question:
A string fastened at both ends has successive resonances with wavelengths of 0.57 m for the nth harmonic and 0.50 m for the (n + 1)th harmonic.
What is the value of n? and What is the length of the string?
If you could please show me how to do it then that would be great, thanks!
2006-11-26 02:16:33 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Physics
length = 3.5m (appr)
n=6
(hint: find GCF of frequencies)
2006-11-26 02:29:43 · answer #1 · answered by oracle 5 · 0⤊ 0⤋
I think you need to solve the equation
0.57n = 0.50(n+1) for the value of n as the nth harmonic should have n wavelengths in the string. Then the length of the string would be 0.57n.
I hope this is right.
2006-11-26 10:27:50 · answer #2 · answered by rscanner 6 · 1⤊ 0⤋
This page will help you develop your own ideas:
http://www.intuitor.com/resonance/swings.html
2006-11-26 10:32:49 · answer #3 · answered by quilm 3 · 0⤊ 0⤋
I have no idear homey. Trying to solve that kind of problem makes me need a drink.
2006-11-26 10:18:39 · answer #4 · answered by Marcus 2 · 0⤊ 1⤋