x=(tanx +cotx)cosecx
2006-11-26 01:19:09 · 5 answers · asked by gg 1 in Science & Mathematics ➔ Mathematics
x=cscxtanx+cscxcotx
=1/cosx+cosx/sin^2x
=sin^2x+cos^2x/sin^2xcosx
=1/sin^2xcosx
=secxcsc^2x
2006-11-26 01:28:11 · answer #1 · answered by raj 7 · 0⤊ 0⤋
x = (tanx +cotx)cscx
x = (sinx/cosx + cos x/sinx)/sinx
x = [(sin^2x +cos^2x)/sinxcosx]/sinx
x = 1/(sin^2xcosx)
x= 1/(1-cos^2x)cosx)
Now you have x all in terms of one trig ratio ( cos x ) , which is the best form for further solutions involving x= something.
2006-11-26 10:42:52 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
x=cscxtanx+cscxcotx
=1/cosx+cosx/sin^2x
=sin^2x+cos^2x/sin^2xcosx
=1/sin^2xcosx
=secxcsc^2x
good luck on your test!!
2006-11-26 09:51:01 · answer #3 · answered by Anonymous · 0⤊ 0⤋
cosecx
----------
tan3x
(where 3 is cubed)...
i dont know..studied it ages ago
2006-11-26 09:26:39 · answer #4 · answered by Anonymous · 0⤊ 0⤋
the question is wrong....i dont know how come it is CALCULS...seems like simple trignometry
2006-11-26 09:23:15 · answer #5 · answered by mannar 2 · 1⤊ 0⤋