2006-11-25 23:21:14 · 4 answers · asked by Kamikaze Pilot 2 in Science & Mathematics ➔ Mathematics
dy/dx=cos x
Integrating both sides, we will get:
y = sinx + c
y(0) = sin0 + c = 0 => c=0
So y=sinx.
2006-11-26 02:12:38 · answer #1 · answered by Kemmy 6 · 0⤊ 0⤋
dy/dx=cos x, if y(0)=0
dy=coxdx
integrate
y= sinx+ C
y=0 when x=0
so, C+sin0=0
C+0 =0
>>>>>C=0
hence,y=sinx
i hope that this helps
2006-11-26 07:47:06 · answer #2 · answered by Anonymous · 0⤊ 0⤋
dy/dx = cosx
implies y = -sinx
Therefore y(0) = -sin0
y(0) = 0
Differentiate wrt x
dy/dx = 0
2006-11-26 09:11:23 · answer #3 · answered by Enrique 2 · 0⤊ 0⤋
integrate both sides wrt to x and you get
y= sinx + c c is a constant of integration
substitute y(0) = 0 to find c
0 = sin (0) + c
0 = 0 + c
so c =0
so the answer is y=sinx
2006-11-26 07:30:36 · answer #4 · answered by Anonymous · 0⤊ 0⤋