I am looking at the advise I have gotten on my question and I now want to know what would be the best way to find out if maybe he is more straight than gay. I have asked him, but he says that he is bi but more gay than straight and wants to be with me. BTW he slept with a girl when we broke up.
2006-11-25 22:23:58 · 8 answers · asked by Mikey75224 2 in Society & Culture ➔ Cultures & Groups ➔ Lesbian, Gay, Bisexual, and Transgender
a closet straight? he told you he is bi but more gay than straight. what's the problem? you want every person in the world to know he is bisexual in the hopes that no one will sleep with him except you...you sound very immature and jealous/obsessive.
2006-11-25 22:56:46 · answer #1 · answered by Spyder 5 · 0⤊ 0⤋
Why would you want to do that? What's more, why do you care? Leave the guy alone. It is not your place or your business. So what, he slept with a girl.
2006-11-26 07:13:15 · answer #2 · answered by Zelda 6 · 1⤊ 0⤋
it's usually BI now, Gay later, sounds like he's a typical male, he wants his cake & eat it too............i was in love with my wife, she's the only woman i've ever been with, but when it was over, i went back to being gay.............it's dangerous to OUT anybody, & really not necessary
2006-11-26 06:54:10 · answer #3 · answered by Anonymous · 0⤊ 1⤋
you never out anyone. that's just hateful. seeking revenge after a break up will make you look like a fool. just let things go
2006-11-26 08:10:41 · answer #4 · answered by Ron N 5 · 2⤊ 0⤋
you dont! Its not your place to OUT anyone. Its their business their life. Mind your own business!
2006-11-26 07:39:52 · answer #5 · answered by david s 4 · 1⤊ 0⤋
Sorry I can't help, try Anne Landers.
2006-11-26 06:26:56 · answer #6 · answered by Anonymous · 0⤊ 0⤋
It is not your place to OUT anyone except yourself.
2006-11-26 06:47:50 · answer #7 · answered by ? 7 · 1⤊ 0⤋
well I would guess that you have no choice but to believe what he says...if not it's none of your business.
2006-11-26 06:59:00 · answer #8 · answered by Anonymous · 1⤊ 0⤋