An object has an acceleration of 6m/s/s?...?

Question

If the net force experienced by the object is increased by a factor of 3.3 and the mass is increased by a factor of 2.5, then the new acceleration would be ___m/s/s??????

Answer 1

Remember Newton's second law: F = ma. You can rearrange that to read a = F/m. So the original acceleration was equal to the original force divided by the original mass. After the adjustments, you have a2 = 3.3F/2.5m. Therefore, a2 = (3.3/2.5)a, or 1.32a. The original acceleration was 6 m/s^2, so the new acceleration is (6*1.32) or 7.92 m/s^2.

Answer 2

Force is mass X accelaration (F = ma) - Force is constant (non changing) or a = F/m
Original accelaration is 6m/s/s
Assuming Force is increased 3.3 times in same direction as original force and mass is increased 2.5 times the accelaration shall be 6 X 3.3 divided by 2.5 (acceleartion being in direct proportion to force and mass causing an indirect proportion impact) gives new accerlation as 7.92 m/s/s

Subhash

Answer 3

F = m * a(0) (A) if we meet the conditions of problem

3.3 F = 2.5 m* ac(1) (B)

dividing B by A 3.3 = 2.5 ac(1) / ac(0) = 1.32

the new acceleration is the old multiplied by 1.32

Answer 4

Accelaration is directly proportional to Force but inversely proportionl to mass.
The accelaration would be 6X3.3/2.5=7.92 m/s/s

Answer 5

F = ma
F=6m
F/m=6
(3.3F)/(2.5m) = a
(3.3/2.5)(F/m) = a
(3.3/2.5)(6) = a
a = 7.92

Answer 6

take the link posted and youll get your answer very simpily