I tried synthetic division but I wasn't able to factor it, any help would be appreciated.
2006-11-25 16:14:08 · 9 answers · asked by my nickname 2 in Science & Mathematics ➔ Mathematics
This is quadratic in x^2 say y
it is y^2+8y -48
= (y+12)(y-4)
= (x^2+12)(x^2-4)
= (x^2+12)(x+2)(x-2)
2006-11-25 18:00:15 · answer #1 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
x^4 + 8x^2 - 48
= x^4 + 12x^2 - 4x^2 - 48
= (x^4 + 12x^2) - (4x^2 + 48)
= x^2(x^2 + 12) - 4(x^2 +12)
= (x^2 - 4)(x^2 + 12)
2006-11-26 00:47:03 · answer #2 · answered by bluestone 2 · 0⤊ 0⤋
(x^2+12)(x^2-4)
2006-11-26 00:16:35 · answer #3 · answered by 19jay63 4 · 0⤊ 0⤋
x^4 + 8x^2 - 48
(x^2+12)(x^2-4)
(x^2+12)(x-2)(x+2)
2006-11-26 01:15:11 · answer #4 · answered by yupchagee 7 · 0⤊ 0⤋
(x^2-12)(x^2+4)
2006-11-26 02:44:39 · answer #5 · answered by deepak k 1 · 0⤊ 1⤋
(x^2 +12)(x^2 - 4)
let's check the middle term:
12x^2 - 4x^2 = 8x^2
2006-11-26 00:21:41 · answer #6 · answered by athena 2 · 0⤊ 0⤋
(X + iâ12)(x -iâ12)(x + 2)(x-2)
Doug
2006-11-26 00:20:38 · answer #7 · answered by doug_donaghue 7 · 0⤊ 0⤋
(x^2+12)(x^2-4)
have fun:D
2006-11-26 00:15:46 · answer #8 · answered by coolchess123 3 · 0⤊ 0⤋
yup
2006-11-26 00:18:35 · answer #9 · answered by Anonymous · 0⤊ 0⤋