If f (x) =16 - x^2 , g (x) = 4 -x . Find (f/g) (x)?

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If f (x) =16 - x^2 , g (x) = 4 -x . Find (f/g) (x)?

2006-11-25 15:30:18 · 5 answers · asked by rlvitte 1 in Science & Mathematics ➔ Mathematics

5 answers

Actually, the answer is *not* 4+x.
(f/g)(x) = (16-x^2)/(4-x)
Now, factorise the top:
(4+x)(4-x)/(4-x).
So *if x is not 4* then (f/g)(x) = 4+x. However, the function is not defined at x = 4.

2006-11-25 15:39:15 · answer #1 · answered by stephen m 4 · 1⤊ 0⤋

(a plus b) into (a minus b) is (a square minus b square). So the answer is 4+x.

2006-11-25 15:37:51 · answer #2 · answered by curious 2 · 0⤊ 0⤋

(f/g)(x) = 4+x

Doug

2006-11-25 15:33:42 · answer #3 · answered by doug_donaghue 7 · 0⤊ 0⤋

aliens aren't real

2006-11-25 15:31:40 · answer #4 · answered by heartcore 3 · 0⤊ 2⤋

f/g(x) = f(x) / g(x)

2006-11-25 15:31:56 · answer #5 · answered by Cassi 2 · 0⤊ 0⤋