What is the formula to figure what the odds are if you have 2 tickets, 3 tickets and so on.
2006-11-25 15:15:11 · 3 answers · asked by tracie a 1 in Science & Mathematics ➔ Other - Science
diidy, how could the odds get worse when you buy more tickets?
I think there are actually two answers, depending on whether each ticket is independent of the others or not.
If each ticket is independent, and there's no guarantee as to how many tickets there are or how many winners there will be, then think of it this way. The odds of any ticket NOT winning are 299:300. Therefore the odds of NO ticket winning are 299^n:300^n, where n is the number of tickets. The odds of at least one ticket winning are 1 - the odds of no ticket winning, or 1 - 299^n:300^n, or (300^n - 299^n):300^n.
If there are 300 tickets of which 1 is a winner, then the odds of winning are n:300.
2006-11-25 15:38:57 · answer #1 · answered by Amy F 5 · 1⤊ 0⤋
Let n = the number of tickets you have
The more tickets you have, the greater your chance of winning. Because each ticket has an equal chance, the formula would be:
n(1/300)
2006-11-25 23:17:59 · answer #2 · answered by Anonymous · 1⤊ 0⤋
n=1(300)
2006-11-26 01:18:26 · answer #3 · answered by Nicholais S 6 · 0⤊ 0⤋