If the perimeter of a rectangle is 22 ft. and the width is 8 ft., find its length.
2006-11-25 14:59:08 · 12 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
2L + 2w = p
2L + 2(8) = 22
2L + 16 = 22
2L = 6
L = 3
2006-11-25 15:01:05 · answer #1 · answered by bgdddymtty 3 · 0⤊ 0⤋
The "width" IS the length because if 1 side is 8 ft, the opposite side has to be 8 ft. Add those 2 sides together and subtract from the 22ft perimeter, the result is only 6 ft left. Divide that 6 ft by 2 to get the true width of 3 ft.
2006-11-25 15:03:38 · answer #2 · answered by KnowhereMan 6 · 0⤊ 0⤋
The perimeter of a rectangle is equal to two times the length plus two times the width (2L + 2W = P).
Knowing the perimeter and the width:
2L + 2(8) = 22
Solve for the length from there.
Hope that helped.
2006-11-25 15:01:32 · answer #3 · answered by Anonymous · 0⤊ 0⤋
the length is 3 ;add both widths =16,subtract it from perimeter 22-16=6; now that for length of both sides which means divide by 2
2006-11-25 15:05:30 · answer #4 · answered by tachyon excelerator 1 · 0⤊ 0⤋
w= 8x2 = 16
p=22
22-16=6
6/2 = 3
length equals 3
2006-11-25 16:06:22 · answer #5 · answered by George 4 · 0⤊ 1⤋
8*2= 16
22-16= 6
6/2 = 3
2006-11-25 15:08:17 · answer #6 · answered by diidy 3 · 0⤊ 0⤋
(22-8*2)/2=3
2006-11-25 15:00:56 · answer #7 · answered by Anonymous · 0⤊ 0⤋
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2016-10-17 13:31:08 · answer #8 · answered by Anonymous · 0⤊ 0⤋
22-8= 14
=D
Next time
PAY ATTENTION IN THE CLASS!
2006-11-25 15:01:42 · answer #9 · answered by Anonymous · 0⤊ 0⤋
22 - (8*2) = n - 22
I assume you know Order of Operations
2006-11-25 15:08:45 · answer #10 · answered by d_skate2000 2 · 0⤊ 0⤋