Heron's formula can only be used when the sides are given. The formula is:
Area = square root of[(s)(s - a)(s - b)(s - c)]
s = (a + b + c)/2
where a,b and c are the sides of the triangle.
Sorry, but there really isn't enough information to work with.
2006-11-25 13:49:16
·
answer #1
·
answered by Akilesh - Internet Undertaker 7
·
2⤊
1⤋
You can get a range of areas as the area is variable. There is a huge variety of triangles with a perimeter of 21.3
The limiting least value = 0 (two lines each 10.65 long)
ie A>0
The maximum value occurs when the triangle is equilateral
ie each side = 7.1
Then A = â[s(s - a)(s - b)(s - c)]
s = 21.3/2 = 10.65
a = b = c = 7.1
So Amax = â[10.65(10.65 - 7.1)(10.65 - 7.1)(10.65 - 7.1)]
= â[10.65(4.51)³]
â 31.26
So 0 < A ⤠31.26
2006-11-25 22:00:44
·
answer #2
·
answered by Wal C 6
·
1⤊
2⤋
http://en.wikipedia.org/wiki/Heron's_formula
Go here, take the formula and plug in the side lengths. It isn't difficult and might help you when this is on a test, as I am certain it will be.
2006-11-25 21:52:40
·
answer #3
·
answered by rrrevils 6
·
0⤊
2⤋
Not enough information to solve.
2006-11-25 21:48:30
·
answer #4
·
answered by Jim Burnell 6
·
1⤊
0⤋
maybe 7.1m, i guessed...
2006-11-25 22:20:01
·
answer #5
·
answered by kaRizzlyn 2
·
0⤊
2⤋
No. You do it.
2006-11-25 21:44:34
·
answer #6
·
answered by That's a Stupid Question 2
·
1⤊
2⤋