i got a serious chem problem, post before but not working, stress!!!?

Question

For the following reaction at a certain temperature, it is found that the equilibrium concentrations in a 5.00 L rigid container are [H2] = 0.0500 M, [F2] = 0.0100 M, and [HF] = 0.400 M. If 0.150 mol of F2 is added to this equilibrium mixture, calculate the concentrations of all gases once equilibrium is reestablished.
H2(g) + F2(g) 2 HF(g)

[H2]
M
[F2]
M
[HF]
M

Answer 1

Keq = [HF]^2/[H2][F2] = (0.4)^2/0.5)(0.1) = 0.16/0.05 = 3.2
Now add 0.150 mole F2.