2006-11-25 10:17:06 · 6 answers · asked by Jessie 1 in Science & Mathematics ➔ Mathematics
If you draw an angle(A) on a graph, the slope of that line will be tan(A)
Opposite = 5
Adjacent =1
Hypotenuse =squareroot(5^2 +1^2) =squareroot(26)
sec(A) = 1/Cos(A) = hypotenuse/adjacent = squareroot(26)/1
sec(A) squareroot(26) is approx . 5.099019514
2006-11-25 18:24:33 · answer #1 · answered by PC_Load_Letter 4 · 0⤊ 0⤋
Tan 0 = 0, not 5. Sec 0 = 1.
2006-11-25 18:19:59 · answer #2 · answered by The Doctor 7 · 0⤊ 0⤋
Formula 1 +tan^2A=sec^2A
so 1+5^2= sec^2A
Sec A=Square root of 26=5.1 Ans.
2006-11-25 18:28:33 · answer #3 · answered by aminnyus 2 · 0⤊ 0⤋
Recall that sec² theta = 1 + tan² theta
So sec theta = sqrt(26)
2006-11-25 18:19:53 · answer #4 · answered by steiner1745 7 · 0⤊ 0⤋
its pi + 0 or 180 + 0 0 being theta
2006-11-25 18:23:27 · answer #5 · answered by pyro_greg 2 · 0⤊ 0⤋
using (tanx)^2 + 1 = (secx)^2
so secx = +/- square root of 26
since angle is in the 1st quadrant, cosx is positive. so secx = 1/cosx is also positive
so secx = square root of 26
2006-11-25 18:20:26 · answer #6 · answered by tidus07 2 · 0⤊ 0⤋