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At what points does the line 4x + 12 = 3y cross the x and y axes?

2006-11-25 10:14:34 · 6 answers · asked by Anonymous in Science & Mathematics Mathematics

6 answers

When you ask where a line crosses the axes (which is generally called the x- or y-intercept), you're essentially asking at which point does either x or y = 0.

Your equation is almost in slope-intercept form (y = mx + b), which will give you the place where the line crosses the y axis (b).
3y = 4x + 12
y = 4/3x + 4
Thus, the line crosses the y-axis at point (0, 4).

To find out where the line crosses the x-axis, just solve for x:
4x + 12 = 3y
4x = 3y - 12
x = 3/4y - 3
The line crosses the x-axis at (-3, 0)

2006-11-25 10:21:15 · answer #1 · answered by bgdddymtty 3 · 0 1

4x + 12 = 3y

1st: (4/3)x + 4 = y

2nd: y-intercept at 4 since the 4 in equation is +4

3rd: Substitute 0 to y in order to find x so:

(4/3)x + 4 = 0
(4/3)x = -4
So x-intercept is -4(3/4) which is -3

x-intercept = (-3,0) y-intercept = (0,4)

2006-11-25 18:36:38 · answer #2 · answered by ? 3 · 0 0

Easy what they are asking your is whats the x and the y equal to. In a case like this set up an x y chart. And solve for each. For example, if x = 1 then according to the chart y=0.

2006-11-25 18:19:06 · answer #3 · answered by .......... 4 · 0 1

It crosses the y axis at x = 0. And it crosses the x axis at y = 0.

2006-11-25 18:19:00 · answer #4 · answered by Anonymous · 0 1

sub 0 for x
12=3y
y=4

sub 0 for y
4x+12=0
4x= -12
x= -3

x-int -3
y-int 4

2006-11-25 18:18:57 · answer #5 · answered by      7 · 0 1

set both y and x equal to zero and find the values for the other one ...
when x = o what does y equal (that is one point)
when y=0 what does xequal (that is another point)

2006-11-25 18:20:44 · answer #6 · answered by travis R 4 · 0 1

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