When you ask where a line crosses the axes (which is generally called the x- or y-intercept), you're essentially asking at which point does either x or y = 0.
Your equation is almost in slope-intercept form (y = mx + b), which will give you the place where the line crosses the y axis (b).
3y = 4x + 12
y = 4/3x + 4
Thus, the line crosses the y-axis at point (0, 4).
To find out where the line crosses the x-axis, just solve for x:
4x + 12 = 3y
4x = 3y - 12
x = 3/4y - 3
The line crosses the x-axis at (-3, 0)
2006-11-25 10:21:15
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answer #1
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answered by bgdddymtty 3
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4x + 12 = 3y
1st: (4/3)x + 4 = y
2nd: y-intercept at 4 since the 4 in equation is +4
3rd: Substitute 0 to y in order to find x so:
(4/3)x + 4 = 0
(4/3)x = -4
So x-intercept is -4(3/4) which is -3
x-intercept = (-3,0) y-intercept = (0,4)
2006-11-25 18:36:38
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answer #2
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answered by ? 3
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Easy what they are asking your is whats the x and the y equal to. In a case like this set up an x y chart. And solve for each. For example, if x = 1 then according to the chart y=0.
2006-11-25 18:19:06
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answer #3
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answered by .......... 4
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It crosses the y axis at x = 0. And it crosses the x axis at y = 0.
2006-11-25 18:19:00
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answer #4
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answered by Anonymous
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sub 0 for x
12=3y
y=4
sub 0 for y
4x+12=0
4x= -12
x= -3
x-int -3
y-int 4
2006-11-25 18:18:57
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answer #5
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answered by 7
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set both y and x equal to zero and find the values for the other one ...
when x = o what does y equal (that is one point)
when y=0 what does xequal (that is another point)
2006-11-25 18:20:44
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answer #6
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answered by travis R 4
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