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A 0.50m long guitar string, of a cross-sectional area 1.0x10^-6 m^2., has a youngs modulas of 2.0x10^-9 n/m^2. how much would you have to stretch the string to get a tension of 20 N?

2006-11-25 08:05:22 · 1 answers · asked by Trevor M 1 in Science & Mathematics Physics

1 answers

Stress = E*strain, where E is the Young's modulus. Then

strain = stress/E

tension = stress times area (total force on the string)
total stretch = strain times length

You can now put it all together

stretch = length * tension / (area * E)

2006-11-25 08:18:32 · answer #1 · answered by gp4rts 7 · 0 0

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