(a over 3 + 4b) - (a over 3 +b)
2006-11-25 07:45:02 · 5 answers · asked by Duchess B 1 in Science & Mathematics ➔ Mathematics
Duch, there's some confusion over what the problem is. It could be a/(3+4b) - a/(3+b) OR a/3 +4b -a/3 -b
If the former, then it boils down to -(11ab)/(9 + 15b + 4b²)
If the later, 3b
2006-11-25 07:57:16 · answer #1 · answered by Steve 7 · 0⤊ 0⤋
easy (-3)-(-3) that makes a over 4b - a over 3 b take away the a makes 4b over b so 4b-b equals 3b
^
2006-11-25 15:49:29 · answer #2 · answered by da man 3 · 0⤊ 0⤋
collect like terms;
a/3 -a/3 +4b -b = 3b
2006-11-25 15:48:44 · answer #3 · answered by modulo_function 7 · 0⤊ 0⤋
a/(3 + 4b) - a/(3 + b)
= a(3 + b)/[3 + 4b)(3 + b)] - a(3 + 4b)/[(3 + b)(3 + 4b)]
= [(3a + ab) - (3a + 4ab]/[(3 + 4b)(3 + b)]
= [3a + ab - 3a - 4ab]/[(3 + 4b)(3 + b)]
= -3ab/[(3 + 4b)(3 + b)]
2006-11-25 16:10:31 · answer #4 · answered by Wal C 6 · 0⤊ 0⤋
-3ab over (a+4b)(3+b)
2006-11-25 15:49:24 · answer #5 · answered by 7 · 0⤊ 0⤋