2006-11-25 07:12:30 · 15 answers · asked by Junior S 1 in Sports ➔ Football (American)
Yes. Their remaining schedule looks relatively easy. They will win the NFC East and get a 1st rd. bye.
I expect them to play in the NFC Championship game if they remain relatively healthy.
2006-11-25 07:15:26 · answer #1 · answered by mesquitemachine 6 · 1⤊ 0⤋
Only if the Giants lose their next few games. But I still think that with the way the Cowboys are playing and their easy schedule (at least compared to the Giants), if they don't make the NFC East Championship, then they may make it in via Wildcard.
2006-11-25 15:47:24 · answer #2 · answered by Anonymous · 0⤊ 0⤋
hell yes they will. first T.O., Jones, Glenn, and Barber. now Romo. there defense is wonderful and they now have a complete offense with Romo instead of Bledsoe. the cowboys not only make the playoffs, they win at least the first round. if now super bowl champs this year, then it will definately be next year
2006-11-25 16:51:57 · answer #3 · answered by emehms 4 · 0⤊ 0⤋
they have favorable schedule and are 7-4 with ten days off- should make playoffs and will likely win division IF they beat Giansy next game.
2006-11-25 15:27:41 · answer #4 · answered by waynestr 2 · 0⤊ 0⤋
No, Because Romo going to fall apart he is not that good he is way overated and he has only been playing 5 games
2006-11-25 15:42:20 · answer #5 · answered by Travis L 1 · 0⤊ 1⤋
If Tony Romo can keep it up, without a doubt yes.
2006-11-25 15:19:59 · answer #6 · answered by Sixteen and Oh 5 · 1⤊ 0⤋
As long as they keep Bledsoe on the bench and Owens doesn't get hurt. Yes they'll make it.
2006-11-25 15:17:14 · answer #7 · answered by neyoneyon 2 · 1⤊ 0⤋
as long as Romo keeps it up i think they will make it to the super bowl if not this year next
2006-11-25 15:33:16 · answer #8 · answered by Donovan 1 · 0⤊ 0⤋
Yes only to get pounded.
2006-11-25 15:51:38 · answer #9 · answered by 10 to 20 5 · 0⤊ 0⤋
HELL YEAH!!!
they are going to make it to playoffs+)
2006-11-25 15:35:42 · answer #10 · answered by Hippy 1 · 0⤊ 0⤋