You can calcuate log to any base easily using the change of base formula.
log base n of b = (log base 10 of b) / (log base 10 of n)
so to calculate log base 2 of 16, for example, divide log 16 by log 2, and you should get 4.
You can also use ln instead of log. It works either way.
2006-11-25 06:04:34
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answer #1
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answered by Jim Burnell 6
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Let x be the number to take the binary log of. I am not familiar with the EL509V, but this should work for any calculator that has any kind of a log on it.
Compute log (2). Save it using the M+ key.
Compute log (x). Divide it by log (2) by hitting divide, MR, =.
The result is log2 (x). It does not matter the base of the logs I use in this - you can use e or 10 or anything for which there are buttons on the calculator for.
This is because log2(x) = log(x)/log(2) for logs to any base b, provided b > 1.
2006-11-25 06:05:06
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answer #2
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answered by alnitaka 4
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I saw an image of this calculator on Google and it does have a log function. It's base 10, but as others said, you can convert log base 2 of x to log of x over log of 2. I don't own one, but my guess is that you should type something along the lines of
log(x)/log(2)
into your calculator, where x is what you wanted to find the log2 of.
2006-11-25 06:08:17
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answer #3
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answered by Anonymous
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Log2 Calculator
2016-10-04 08:50:42
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answer #4
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answered by ? 4
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Most calculators only give you base e and base 10 logs.
For other bases, use this:
x = x
2^(log2(x)) = 10^(log10(x)) , see what I've done?
Now you can solve for log2(x) by converting 2 into 10^log10(2)
10^(log10(2)*log2(x)) = 10^(log10(x))
log10(2)*log2(x) = log10(x)
log2(x) = log10(x)/log10(2)
That's pretty long winded by the final result works.
2006-11-25 06:02:29
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answer #5
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answered by modulo_function 7
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u can only get log to the base 10 or natural log (ln) on ur calculator.
2006-11-25 06:01:54
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answer #6
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answered by Just me 5
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