Two campers dock a canoe. One camper has a mass of 100.0 kg and moves forward at 3.0 m/s as he leaves the canoe to step onto the dock. With what speed do the canoe and other camper move if their combined mass is 175.0 kg?
2006-11-25 05:49:04 · 5 answers · asked by lindi 2 in Science & Mathematics ➔ Physics
conservation of linear moment:
m1*v1 = m2*v2
m1*v1/m2 = v2
(100.0 kg)(3.0 m/s)/(175.0 kg) = v2 = 1.71 m/s
2006-11-25 05:57:23 · answer #1 · answered by Anonymous · 0⤊ 0⤋
the other guy should be moving with speed of 4 m/s
2006-11-25 13:53:56 · answer #2 · answered by So_Hot_An_Ice 2 · 0⤊ 0⤋
If you want to conserve momentum, then
m1*v1 = m2*v2
2006-11-25 13:54:42 · answer #3 · answered by modulo_function 7 · 0⤊ 0⤋
Sorry,I don't know.
2006-11-25 14:12:47 · answer #4 · answered by Anonymous · 0⤊ 0⤋
1.7 m/s
2006-11-25 13:57:30 · answer #5 · answered by Nelly 2 · 0⤊ 0⤋