1. 9x
2. 97m^2n^2
2006-11-25 05:16:51 · 4 answers · asked by indiangirl!=D 3 in Science & Mathematics ➔ Mathematics
1.9x=3*3*x
2.97m^2n^2
=97*m*m*n*n
2006-11-25 05:22:01 · answer #1 · answered by raj 7 · 1⤊ 0⤋
factors and not prime factors:
1. 9x = 1.9x
= 1.9.x
=3.3x
=3.3.x
so the factors are 1,3,3x,9,9x,x
2. 97m^2n^2
= 1.97m^2n^2
= 97.m^2n^2
=97.m.m.n^2
=97.m^2.n.n
=97.mn.m.n
= 97.m^2.n^2
= 97m^2n.n
=97mn^2.m
so the factors are:
1, 97, m^2,n^2, mn,m,n,mn^2, m^2n, m^2n^2,97m^2n^2,97m,97n,97mn,
97m^2,97n^2,97mn^2,97nm^2
97mn^2,97m^2n
2006-11-25 05:35:35 · answer #2 · answered by anami 3 · 0⤊ 0⤋
1) The factors are 3*3*x
2) The factors are 97* m*m*n*n
97 is a prime number and so has no factors
2006-11-25 05:23:41 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
????????????????????? how should i no!
2006-11-25 05:18:26 · answer #4 · answered by Anonymous · 0⤊ 3⤋