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2006-11-25 03:13:04 · 13 answers · asked by arthi s 1 in Science & Mathematics Physics

13 answers

gravity is a special case of gravitation.It is the force by which earth pulls a one kg object towards it.

ie g=GM/R^2
M=mass of earth
R=Radius of earth

now force acting on a object of mass 1 kg at a height h(from earths surface) will be
f=GM/(R+h)^2
we can take out R out of bracket so that (R+h)^2 can be R^2{1+h/R}^2
Now
GM/R^2=g
So we can easily WRITE it as
f= g/{1+h/R}^2

This f is that something we usually write as g'

Now g' can be written as g{1+h/R}^(-2)

FOR NOT TOO SOPHISTICATED CALCULATION
IT CAN BE REDUCED USING BINOMIAL THEORM TO
g'=g{1-2h/R}

2006-11-25 05:26:05 · answer #1 · answered by vivek 2 · 0 0

To say that more precisely, it is the variation of acceleration due to gravity (on earth) with altitude.

The gravitational force acting on any object is inversely proportional to its distance from the centre of the earth. So will be the acceleration due to gravity.

If it is at an altitude h, the g at height h, g(h), is proportional to 1/(R+h)^2 -- (R is the earth's radius)
>>
g(h) = g(0) (R^2 / (R+h)^2)
>>
g(h) = g(0) ( 1 / (1 + h/R)^2)
This defines the variation with altitude.

2006-11-27 19:47:37 · answer #2 · answered by Seshagiri 3 · 0 0

F = GMm/r^2; where G is a constant, M is a mass (like Earth), m is a mass (like you), and r is the distance between the centers of the two masses. F is the pull (force) of gravity.

As you can see from the equation, if r gets bigger, the force F gets smaller. r gets bigger as you move farther and farther away from the center of the Earth for example. In other words, r gets bigger as you gain altitude and move away from the center of the Earth.

The lessons to learn here...G in this equation is NOT the same g in W = mg; where weight (W) is a mass times the acceleration due to gravity (g). G and g are related, but they are not the same value nor do they have the same physical meaning.

Also, the main point, the force of gravity (F) varies as the inverse square of the distances (1/r^2) between the centers of the two masses (M and m). For example, if you double the distance, the force between the two masses will be 1/4 what it was originally

2006-11-26 17:24:52 · answer #3 · answered by praveenplp 2 · 0 0

The equation you are looking for is:

F = GMm/r^2; where G is a constant, M is a mass (like Earth), m is a mass (like you), and r is the distance between the centers of the two masses. F is the pull (force) of gravity.

As you can see from the equation, if r gets bigger, the force F gets smaller. r gets bigger as you move farther and farther away from the center of the Earth for example. In other words, r gets bigger as you gain altitude and move away from the center of the Earth.

The lessons to learn here...G in this equation is NOT the same g in W = mg; where weight (W) is a mass times the acceleration due to gravity (g). G and g are related, but they are not the same value nor do they have the same physical meaning.

Also, the main point, the force of gravity (F) varies as the inverse square of the distances (1/r^2) between the centers of the two masses (M and m). For example, if you double the distance, the force between the two masses will be 1/4 what it was originally.

2006-11-25 03:33:35 · answer #4 · answered by oldprof 7 · 0 0

As altitude increases, the earth's gravitational force will decrease.. thats why, in space, there is no Gravity..and astronauts feel the weightlessness....

As altitude decreases, the "G" will increase.. there's a funny calculation about this also...
If some body dig the earth along its diameter from one side to other side and they suspend a simple pendulam along the diameter, the time period to make one oscillation is about 82 minutes ( i read in Physics about 10 yrs back..but its true)...
this is because , "G" will increase as altitide decreases..

Hope this helps you....

Good luck

2006-11-25 03:20:46 · answer #5 · answered by murthy 3 · 0 0

It is an inverse square relationship.

But is is not noticeable on earth, lots of other factors play roll, but in space at certain altitude it is close to zero but never zero.

2006-11-25 03:45:11 · answer #6 · answered by minootoo 7 · 0 0

The only things that are considered for performance enhancement are the wind and altitude.

2016-05-23 01:20:18 · answer #7 · answered by Anonymous · 0 0

gravitational force is inversely proportional to the square of the distance between the centre of the two bodies
more the distance, lesser the force

2006-11-25 03:25:19 · answer #8 · answered by sushobhan 6 · 1 0

as we move higher and higher from the surface of the earth the force of gravity decreases and thennumerical value is equal to
g=(m-2h/r)

and as we move down the earths surface it decreases lesser as compared to while moving up
g=(m-h/r)

2006-11-25 19:34:48 · answer #9 · answered by samrat_nighthawk 1 · 0 0

Inverse square.

2006-11-25 03:16:10 · answer #10 · answered by Anonymous · 1 0

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