Algebra Help!!!!!!!?

Question

there are a total of 500 douglas fir and ponderosa pine trees in a section of forest bought by hoodoo logging CO. The company paid an average of $300 for each douglas fir and $225 for each ponderosa pine. If the company paid 217,500 for the trees how may of each did the company buy?

Answer 1

D+P=500
300D+225P=217500
dividing by 75
4D+3P=2900
-3D-3P=-1500 (1)*-3
adding
D=1400
something wrong with the problem
even if all the trees were douglas the total price will be only 150,000

Answer 2

let x be number of douglas fir and y number of ponderosa pines

You can write x+y =500 (1)

anf for the price 300 x +225y =217500(2)

(1) gives x = 500-y rplace this in (2)

300 (500 -y) +225 y = 217500


THere is an error in your since you find for the price a negative answer

Check !!

Answer 3

unsolvable case as the question is illogical.
douglas fir = 1400 and pine trees = -900
I guess the question must have some typo error

Answer 4

They can never pay as much as 217,500 for the trees.
Imagine they buy 500 of the most expensive one, they would spend 300*500 = 150 000 !

Answer 5

500 douglas fir trees = 150,000 dollars

they paid too much, hoodoo logging co got ripped off man!!!!

Answer 6

The answer is:
4x+3y = 2900
x = 1400
y = -900
And the douglas fir trees cost x=1,400 and the ponderesa pine trees cost y=900

GOOD LUCK !
I STUDY CALCULUS AND ALGEBRA,I LIKE IT !

Answer 7

"X" amount of douglas fir and "Y" amount of ponderosa pine

Answer 8

Just a thought, have you considered doing your own homework? A question once in a while, fine, but this is two in 4 minutes. . .

Answer 9

Tasha J you asked too much problems so this is a test Cheater!

Answer 10

x+y = 500

300x+225y = 217500

or 4x+3y = 2900

or x = 1400

and y = -900

Something's wrong,