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[H+] = 10-pH = 10-2.12 = 7.6 x 10-3 M H+?

how can i figure out that 10 with PH of -2.12 is 7.6E-3 M H+

2006-11-24 21:08:27 · 2 answers · asked by tanny 1 in Science & Mathematics ➔ Chemistry

how do i antilog

2006-11-24 21:30:30 · update #1

2 answers

use this pH= -lg[H+]

2006-11-24 21:37:25 · answer #1 · answered by ninjatortise 2 · 0⤊ 0⤋

Antilogs.

2006-11-24 21:18:54 · answer #2 · answered by ag_iitkgp 7 · 0⤊ 0⤋

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