2006-11-24 19:52:49 · 26 answers · asked by PANKAJ J 1 in Science & Mathematics ➔ Mathematics
Well, they used only one digit, which is 9. Mine is
(((...(((12!)!)!)!...!)!)!
= infinity
^_^
2006-11-24 20:21:17 · answer #1 · answered by kevin! 5 · 0⤊ 0⤋
9+n
2006-11-24 20:38:39 · answer #2 · answered by G-Unit 3 · 0⤊ 0⤋
Simple number is 99.
For operations
multiplication 9*9 = 81
addtion 9+9 = 18
Power 9^9 = 387420489 [But, thats not 2 digits, i am afraid].
Binary number to 99 is 1100011.
Factorial 99! = 9.332621544394415e+155
So, factorial indeed would giveyou largest number with two digits 99.
I hope thats the answer.
All the best
2006-11-25 00:03:31 · answer #3 · answered by Paritosh Vasava 3 · 0⤊ 0⤋
9 to the power of 9.
2006-11-24 19:54:42 · answer #4 · answered by Anonymous · 0⤊ 0⤋
If we can use hex I would say F^F power which would be 15 up to the 15th power.
Otherwise 99! (99*98*97....)
or 9^9 (Depending on your level of math)
MikeC
2006-11-24 20:10:24 · answer #5 · answered by MikeC 3 · 0⤊ 0⤋
99
2006-11-24 20:00:35 · answer #6 · answered by Venkatesh 1 · 0⤊ 0⤋
id say 9 to the power of 9 at a guess
2006-11-24 19:57:00 · answer #7 · answered by cadippoz 1 · 0⤊ 0⤋
is it 9^9
2006-11-24 20:24:35 · answer #8 · answered by Anonymous · 0⤊ 0⤋
using the hex decimal system F^F would be the largest number witch would be 613B62C597707EF in base 16 or 437893890380859375 in base 10
2006-11-24 20:10:02 · answer #9 · answered by Male_42_us 2 · 0⤊ 0⤋
thats what I was going to say - but lets cheat 9 to the power of 9 billion
2006-11-24 19:57:07 · answer #10 · answered by Norman 7 · 0⤊ 0⤋
If were allowed factorials then zz! in base 26 otherwise z^z (i.e 25^25 in base 10)
2006-11-25 08:59:35 · answer #11 · answered by spoon_bender001 2 · 0⤊ 0⤋