a farmer walks on boundary of a square field of side10m in 40s. what is displacement in 2min 20s?

Answer 1

Unknown.

Your question is incomplete and poorly writen.

Answer 2

The previous answer is wrong.

After 2 min, 20 sec, the farmer will have done 3 1/2 laps of the square field, so the farmer is halfway around from where he started. This leaves a range of possible answers.

Assuming the farmer started at a corner, the pythagorean theorem tells us that he is about 14.1 meters away. 10^2+10^2=c^2. However, if he started at the midpoint of a side, he would now be on the midpoint of the opposite side and only 10 meters displaced.

So the answer to the question is somewhere between 10 and 14.1 meters away, depending on where he started.

Answer 3

the previous answer is misguided. After 2 min, 20 sec, the farmer might have performed 3 a million/2 laps of the sq. field, so the farmer is halfway around from the region he began. This leaves countless a threat ideas. Assuming the farmer began at a corner, the pythagorean theorem tells us that he's approximately 14.a million meters away. 10^2+10^2=c^2. in spite of the easy certainty that, if he began on the midpoint of a area, he could desire to now be on the midpoint of the different area and in certainty 10 meters displaced. So the answer to the question is someplace between 10 and 14.a million meters away, relying on the region he began.

Answer 4

THE distance travelled in 40s is 40m
in 140s it's 140m
after 2 min he is at original position
now he travels 20m ahead on the boundary
so he is at the opposite vertex
since displacement is the smallest possible distance from the initial position,
using pythagorus theorem,
it's 10root2
approx 14.14m


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Answer 5

he needs 4*40= 160 sec (2min 40sec)to walk along all the sides ..but his displacement bcomes zero as he reaches the starting position (as displacement is the shortest distance between the initial and final positions). but he travelled only 2min 20sec ...by that time he is in the middle of last side that is 5 meters away from the starting point..which is his displacement.

Answer 6

displacement is the shortest distance from the initial to the final. by the end of 2 min 20 secs he will at the diagonally opposite corner from where he started and the shortest distance is 10root2.(length of the diagonal of the square) that is 14.14m(approx)

Answer 7

2 min 20 sec =140 sec
since 40 sec =10 m
140 sec =10*140/40
= 140/4 = 35 m
displacement =35 m

Answer 8

It depends on from where farmer starts to walk

There are two answers.


14.142 meters. or 10 m

10m x 4 = 40 Meters in 40 Sec.

i.e. 1 meter/sec is speed

2min 20 sec = 140 sec.

i.e. 140 meters in 140 sec.

If he starts from one corner he travels 14 sides. i.e. he reches opposit corner.

Distance between opposit corners of 10 m x 10 M sq is
square root (10^2 + 10^2) = 14.142

So displacement is 14.142 meter

But if starts from middle of side. He will reach middle of opposit side. ie. distance will be 10 m.

Answer 9

in 40s he completes the full round of the field
2min20s=140s , hence he completes two rounds of the field +two sides
therefore by pythagoras theorem
10^2+10^2=L^2
L=1.414x10
L=14.14meters

Answer 10

2 min 20s=140s . At 80 s he walks 20ms .and similarly at 140s the displacement is 35mts.