For calculus, if f(x) equal 1/x, what kind of a value is it and what kind of relation to f(x)?

Question

How would it look on a graph?

Answer 1

if you have a TI-89 then go to your y= area and enter this into y1

y1 = 1 / x

then hit graph

or

by hand, it just means that f(x) = 1 / x

so

if x = 7 and u need to solve for f (x)
then

f(7) = 1 / 7

get it?

Answer 2

If f(x) = 1/x, then this function is an hyperbola. As x -> (tends to) zero from the positive side, f(x) -> +infinity. As x -> 0 from the negative side, f(x) -> negative infinity. As x -> negative infinity, f(x) will tend to zero from below, as x -> +infinity, f(x) will tend to zero from above.
If y = 1/x, then the graph will be reflected in the line y = x, and also in the line y = -x.
Unfortunately, it's a bit hard to illustrate graphs using this format: I'd suggest you get a large sheet of quadrille paper, and plot some values. (Remember to plot values for x < 0 as well as x > 0.)

Answer 3

x can take any value other than zero.

On graph, it represents parabolic (hope correct term!) in 1st and 3rd quarters (tending to touch both x and y axes at infinity), as the equation works out to xy=1.

Answer 4

It's a real-valued function everywhere except at x = 0.

The relationship of f(x) to 1/x is that they are one and the same thing.


Doug

Answer 5

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Answer 6

f(x)=1/x is a reciprocal function so much so the function is the multiplicative inverse of the variable