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(2xy³)(-5x²y²)

2006-11-24 17:31:07 · 6 answers · asked by Anonymous in Science & Mathematics Mathematics

6 answers

2xy^3)(-5x^2y^2)
=(2X-5)(x^[1+2]y^[3+2])
=-10x^3y^5

2006-11-24 17:37:54 · answer #1 · answered by alpha 7 · 1 0

I cannot see the powers clearly, but from what I can see,

= 2xy^3 . * . -5x^2y^2 ( multiply )
= 10x^3y^5


Multiply the first term with the second term.

( When you multiply, the powers add. For example y square *y cube = y to the power 5, because the powers add ( 2 + 3 ). )

2006-11-25 01:40:09 · answer #2 · answered by M 1 · 0 0

treat everything separately and remember you add indices. You can put an"x" between the brackets to show that it is multiplication.
(2xy^3)(-5x^2y^2) becomes -(2xy^3)(5x^2y^2) to
-(10xy^3)(x^2y^2) to -10(xy^3)(x^2y^2) to
-10(x^3y^3)

2006-11-25 03:20:48 · answer #3 · answered by Anonymous · 0 0

i believe....

-you would follow the pemdas format (parenthesis, exponents, multiply or divide (which ever comes first), add or subtract (which ever comes first).

-you keep what is in each set of parenthesis by them self. So (2xy) will be solved separetly from (-5xy). After you solve them separetly you multiply each set together because if there is nothing between parenthesis or variables you multiply.

-you also cant add or subtract variables to numbers

2006-11-25 01:39:38 · answer #4 · answered by Garret 2 · 0 0

(2xy³)(- 5x²y²) =

- 10x³y^5

- - - - - - -s-

2006-11-25 09:12:11 · answer #5 · answered by SAMUEL D 7 · 0 0

ggggggggggggggggggggggggggggggggggg

2006-11-25 01:49:37 · answer #6 · answered by Anonymous · 0 0

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