2xy^3)(-5x^2y^2)
=(2X-5)(x^[1+2]y^[3+2])
=-10x^3y^5
2006-11-24 17:37:54
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answer #1
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answered by alpha 7
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I cannot see the powers clearly, but from what I can see,
= 2xy^3 . * . -5x^2y^2 ( multiply )
= 10x^3y^5
Multiply the first term with the second term.
( When you multiply, the powers add. For example y square *y cube = y to the power 5, because the powers add ( 2 + 3 ). )
2006-11-25 01:40:09
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answer #2
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answered by M 1
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treat everything separately and remember you add indices. You can put an"x" between the brackets to show that it is multiplication.
(2xy^3)(-5x^2y^2) becomes -(2xy^3)(5x^2y^2) to
-(10xy^3)(x^2y^2) to -10(xy^3)(x^2y^2) to
-10(x^3y^3)
2006-11-25 03:20:48
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answer #3
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answered by Anonymous
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i believe....
-you would follow the pemdas format (parenthesis, exponents, multiply or divide (which ever comes first), add or subtract (which ever comes first).
-you keep what is in each set of parenthesis by them self. So (2xy) will be solved separetly from (-5xy). After you solve them separetly you multiply each set together because if there is nothing between parenthesis or variables you multiply.
-you also cant add or subtract variables to numbers
2006-11-25 01:39:38
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answer #4
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answered by Garret 2
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(2xy³)(- 5x²y²) =
- 10x³y^5
- - - - - - -s-
2006-11-25 09:12:11
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answer #5
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answered by SAMUEL D 7
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ggggggggggggggggggggggggggggggggggg
2006-11-25 01:49:37
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answer #6
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answered by Anonymous
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