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2a⁴b + 8a²b² - 2a²b⁴

2006-11-24 17:08:33 · 5 answers · asked by Foxglove 2 in Science & Mathematics Mathematics

5 answers

take the lowest of every term out variables and numerals:

2 in terms of numeral, a^2 in terms of the variable a, and

b in terms of the varaible b

2a^2b( a^2 + 4b - b^3)

2006-11-24 17:09:56 · answer #1 · answered by Zidane 3 · 0 1

Well, to get the common factor, you must find the lowest exponent of each variable, and coefficient.

In this case, 2 is a common coefficient, a² is the least exponent for a, and b is the least exponent of b.

Therefore, 2a²b is the common factor.

To factor out, you rewrite the expression as the product of the common factor and the expression divided by this factor.

Thus,

= 2a²b(a² + 4b - b³)

^_^

2006-11-25 04:25:09 · answer #2 · answered by kevin! 5 · 0 0

2a^2b(a^2+4b+b^3)

^ means raise the number before the ^ symbol to the power after the ^ symbol

a^2 = a squared

2006-11-25 01:11:25 · answer #3 · answered by diburning 3 · 0 0

2(a^4)b + 8a²b² - 2a²(b^4)
= (2)(a)(a)(a)(a)(b) + (2)(2)(2)(a)(a)(b)(b) + (2)(a)(a)(b)(b)(b)(b)
= 2a²b(a² + 4b + b³)

2006-11-25 01:51:01 · answer #4 · answered by Anonymous · 0 0

2a^4b = 2 * a *a * a* a *b
8a^2b^2 = 2 *2*2*a*a*b*b
2a^2b^4 = 2*a*a*b*b*b*b

so underline those values which are common in all
it is 2*a*a*b ( a*a + 2*2*b - b*b*b)

2006-11-25 03:28:51 · answer #5 · answered by @rrsu 4 · 0 0

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