x^2-4x-12 /[divided by] 5x^2-180. Anyone feel like they have the answer and or can tell me how to do it ?
2006-11-24 14:10:23 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(x+2) / [5(x+6)]
x^2-4x-12 = (x-6)(x+2)
5x^2-180 = 5[x^2-36] = 5(x+6)(x-6)
both the numerator and the denominator have the factor (x-6) so those cancel. You are left with:
(x+2) / [5(x+6)]
2006-11-24 14:13:07 · answer #1 · answered by krbmeister 2 · 1⤊ 0⤋
x² - 4x - 12 = (x -6)(x + 2)
5x² - 180 = 5(x² - 36) = 5(x + 6)(x - 6)
[(x + 6)(x + 2)] / [5(x + 6)(x - 6)] --- The (x + 6)'s cancel out...
(x + 2) / 5(x - 6)
2006-11-24 22:21:10 · answer #2 · answered by Anonymous · 0⤊ 0⤋
x^2 - 4x - 12 / 5x^2 - 180
(x - 6) (x + 2) / 5 (x^2 - 36)
(x - 6) (x + 2) / 5 (x - 6) (x + 6)
(x + 2) / 5(x + 6)
(x + 2) / (5x + 30)
does that get you started....
2006-11-24 22:17:21 · answer #3 · answered by Anonymous · 0⤊ 1⤋
x² - 4x - 12 factors to (x - 6)(x + 2).
5x² - 180 factors to 5(x² - 16) = 5(x - 6) (x + 6)
Cancel terms and you're left with
x+2
--------
5(x+6)
2006-11-24 22:18:39 · answer #4 · answered by Jim Burnell 6 · 0⤊ 0⤋
75 I did on E-calculator
2006-11-24 22:20:59 · answer #5 · answered by p.cahill 2 · 0⤊ 1⤋
i really wish i could help you, but i cant good luck to you :)
2006-11-24 22:19:10 · answer #6 · answered by shelby m 3 · 0⤊ 1⤋