I have a cube the surfave area of each side is 1 I have to find the diagonal?

Answer 1

If it's a cube, all sides have to be squares.

If the surface area of one side is 1, then the the length of each edge is also 1.

Then, the diagonal of a side would be √(1² + 1²) = √2

And, not sure if this is what you're asking, a diagonal connecting one corner of the cube to the opposite corner would have the diagonal of one side as a base, and an edge as the other side, so it would have length √(1+2) = √3

Answer 2

The area of each side is 1, so
A = s²
s² = 1
s = 1

The side measures 1. The diagonal measures
d = s√3

Therefore,
d = √3

^_^

Answer 3

Take the cube and set one vertex on the origin in the first octant.
You can draw a vector from the origin to the point (1,1,1) this is the diagonal.

By pythagoreans theorem the length of a vector is sqrt(x^2+y^2+z^2).

so this vector is sqrt(3)

Answer 4

diagonal = √(3)*s
= √(3s²)
= √3 as s² = 1

Answer 5

2^1/2
Cube w/ surface 1sq side ea. edge =1
Apply Pythagorean theorem