A 0.0100 M solution of nickel II is buffered at PH 8.0 with a non complexing (alphaNi=1.0) buffer and titrated

Question

with 0.0100 M EDTA.Calculate pNi at (a)50% (b)100% (c)200% titration

logKNi=18.6
alphaY=10^-2.2

Answer 1

Your question is not very clear to me.
What are alphaNi and alphaY ?
Alpha can be used for lots of different things like activity, dissociation degree, coefficient for chaning molarity to normality, etc but here I fail to see what it represents, especially alphaY (what is Y?).

If the complexation equilibrium constant is truly 10^18.6 then the reaction is practically quantitative and at 100% and 200% [Ni+2] will practically approximate zero and the pNi will be huge. If you want us to help you find exact values please clarify your question and send me an email to edit my answer accordingly.