Estimate the force a person must exert on a string?

Question

Estimate the force a person must exert on a string attached to a 0.200 kg ball to make the ball revolve in a horizontal circle of radious 0.600 m. The ball makes 1.00 revolutions per second. Do not ignore the weight of the ball. In particular, find the magnitude of FT, and the angle it makes with the horizontal. [Hint: Set the horizontal component of FT equal to maR; also, since there is no vertical motion, what can you say about the vertical component of FT?]

I have solved this question and got the answers 4.74 or 4.76, both or which are wrong. I can't seem to find an error in my solution, but if you can please inform me. Thanks

Ft= ?N
(theta)= ?(degrees)

answers 4.74 & 4.76 are to first question

Answer 1

Fg = mg = (0.20 kg)(9.80662 m/s^2) = 1.961324 N
Fc = (mv^2)/r = mrω^2
Fc = (0.20 kg)(0.60 m)((2π rad/s)^2
Fc = 4.73741 N
Ft = √( 4.73741^2 + 1.961324) @ arctan(1.961324/4.73741)
Ft ≈ 5.127 N @ 22.5°

[The vertical component of Ft must offset the weight of the ball.]