2006-11-24 13:18:38 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Either we have BBBGGG or GGGBBB. In both cases, there are 3! ways of arranging boys, and 3! ways of arranging girls. So 3!*3!*2 = 72.
2006-11-24 13:21:45 · answer #1 · answered by stephen m 4 · 1⤊ 0⤋
15, i think of of. 6*5/a million*2=15 no wait, 6*5*4/a million*2*3 = 20 / no, this isn't any longer the staggering formula, in spite of the certainty that it the staggering answer. there is the question, is bbbggg equivalent to gggbbb? this set is with B first. there is an identical set with G first. a million. bbbggg 2. bbgggb 3. bbggbg 4. bbgbgg 5. bgggbb 6. bggbgb 7. bggbbg 8. bgbbgg 9. bgbgbg 10 bgbggb
2016-10-17 12:11:22 · answer #2 · answered by graviett 4 · 0⤊ 0⤋
2 * 3! * 3! = 72
2006-11-24 13:22:20 · answer #3 · answered by Wal C 6 · 0⤊ 0⤋
17 ways.
2006-11-24 13:22:57 · answer #4 · answered by Ashwin M 3 · 0⤊ 1⤋
don`t know but it sounds like fun
2006-11-24 13:26:16 · answer #5 · answered by Anonymous · 0⤊ 1⤋
where you sit and thing these type of question??????????????
2006-11-24 19:39:57 · answer #6 · answered by sam 3 · 0⤊ 0⤋