i have to unfoil. I got (x-4) (x-4) am I right?
2006-11-24 11:57:59 · 15 answers · asked by Jeff Mad. 2 in Science & Mathematics ➔ Mathematics
Looks good to me.
2006-11-24 12:01:37 · answer #1 · answered by bartman40467 4 · 1⤊ 0⤋
You got it right. You can always plug in a couple of numbers in the equation (say 0, 1, etc) to verify your answer. For example putting "0" for x, you'll get:
0^2-8*0+16=16
(0-4)(0-4)=16
Of course this is not 100% foolproof (unless you try a lot of numbers), but it helps a lot. Besides 0, 1 and 2 are my other favorites to plug in.
2006-11-24 20:03:15 · answer #2 · answered by emrahboston 2 · 1⤊ 0⤋
yup you got it right! not simplified x^s-8x+16 is the same as x^2-4x-4x-16.
so the answer (x-4) (x-4) is correct!
2006-11-24 20:05:53 · answer #3 · answered by Rachel 2 · 1⤊ 0⤋
which two numbers that multiply to 16 and add up to -8?
is it -4 and -4
(x-4)(x-4)
2006-11-24 20:02:32 · answer #4 · answered by 7 · 1⤊ 0⤋
x² + bx + c = (x + m)(x + n)... where (m)(n) = c and m + n = b
x² - 8x + 16 = (x - 4)(x -4) = (x - 4)²
You are correct! Great job!
2006-11-24 20:05:18 · answer #5 · answered by Anonymous · 1⤊ 0⤋
correct otherwise ( x-4)^2
2006-11-25 03:59:41 · answer #6 · answered by sam 3 · 1⤊ 0⤋
Yup. a^2 - 2ab + b^2 is always (a - b)^2
2006-11-24 20:00:32 · answer #7 · answered by bgdddymtty 3 · 2⤊ 0⤋
That's the right answer!
2006-11-25 00:05:38 · answer #8 · answered by Anonymous · 0⤊ 0⤋
Absolutely - good job
2006-11-24 20:01:41 · answer #9 · answered by IDP 2 · 1⤊ 0⤋
(x-4)(x-4)....
2006-11-24 20:03:43 · answer #10 · answered by iVan_16 1 · 1⤊ 0⤋