When you want to balance ANY chemical equation, always follow these steps:
1. Balance metals
2. Balance non-metals
3. Balance hydrogen
4. Balance oxygen
Let's do it
First let's balance K (metal):
"2" KHCO3 + __H3PO4 yields __K2HPO4 + __H2O + __CO2
done. now let's balance P (non metal): if you check, it is balanced already.
now C (also non metal):
2 KHCO3 + __H3PO4 yields __K2HPO4 + __H2O + "2" CO2
now hydrogen:
2 KHCO3 + __H3PO4 yields __K2HPO4 + "2" H2O + 2 CO2
finally, oxygen (its already balanced!!)
So you end with
2 KHCO3 + H3PO4 yields K2HPO4 + 2 H2O + 2 CO2
2006-11-24 12:00:40
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answer #1
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answered by Ferts 3
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well,,,,
start with the distribution of atoms BEFORE you start balancing....
K 1, 2
So, you know you have to put at least a 2 in the very front.
_2_KHCO3 + __H3PO4 yields __K2HPO4 + __H2O + __CO2
that gives us then two carbons on the left, so we need two carbons on the right
_2_KHCO3 + __H3PO4 yields __K2HPO4 + __H2O + _2_CO2
now, we have five hydrogen on the left, on the right, there is one in K2HPO4 and two in H20, so, I can double the water...
_2_KHCO3 + __H3PO4 yields __K2HPO4 + _2_H2O + _2_CO2
there's one Phosphorus on each side, that's cool, and ten Oxygens.on the left ( 6 plus 4) .. on the right we have 4 + 2 + 4 is ten, cool. We're done.
2006-11-24 11:56:54
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answer #2
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answered by rboatright 3
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2 KHCO3 + H3PO4 --> K2HPO4 + 2 H2O + 2 CO2
2006-11-24 11:57:33
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answer #3
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answered by physandchemteach 7
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2KHCO3 + 1H3PO4 -----> 1K2HPO4 + 2H2O + 2CO2
Element by element analysis
products ------------> reactant
2K --------------------> 2K
2H + 3H = 5H-------> H + 4H = 5H
2C --------------------> 2C
6O + 4O =10 O----> 4 O + 2 O + 4 O = 10 O
1P --------------------> 1P
it checks.
2006-11-24 11:57:10
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answer #4
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answered by Jess 2
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2KHCO3 + H3PO4 ----> K2
2006-11-24 12:01:35
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answer #5
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answered by connor0314 3
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P2O5 +KHCO3 =
2015-06-30 07:14:30
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answer #6
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answered by Natalie 1
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