physics question help please!!!!!?

Question

will the acceleration of a car be the same when the car travels around a sharp curve at a constant 60km/h as when it travels around a gentlecurve at the same speed? explain

PLEASE!!

Answer 1

Firstly, let me point out to you which answers are wrong and which answers are right. Otherwise you'll be just as confused as you were to begin with.

The first answer is confused. The second and third answers have no idea of what their talking about. The other answers are correct.

Here's why the first answer is confused:

Speed and velocity use exactly the same units.
So it is perfectly acceptable to say "a car travels around a sharp curve a 60 km/hr".

Restated, what we are saying is that the car moves around a curve at constant speed of 60 km/hr. The statement above does not include directional information.

(However, suppose we said "a car travels around a sharp curve with constant velocity of 60 km/hr". Then, clearly this would be wrong. Velocity does change as it goes around the curve.)

Secondly, let us recall some basic facts of 'Uniform Circular Motion'
An object that travels with Uniform Circular Motion has:
- constant speed
- changing velocity
- acceleration towards the centre

Now, the car in question displays uniform circular motion. This is so even though we are considering a partial circular path.

So, we can use this import formula (you should memorise it)

ar = v ^2 /r

This relates the centripetal acceleration, ar, to the radius of the circle (or in the case of a partial circle, the radius of curvature), r.

From the formula you can see that a sharp bend, i.e. a small r, will give a larger value of centripetal acceleration compared to a gentle bend, i.e a large r.

Substitute v=60 and different values of r into the formula above to verify this.

Answer 2

All the answers given for this question are wrong because they do not take into account that when the car travels around a curve its speed no doubt is constant but its direction of motion is changing so velocity is changing. Therefore there is an acceleration called centripetal acceleration which always acts normal to the direction of the velocity, hence changes only its direction and not magnitude. Mathematically it can be derived to have magnitude as (v.v)/r, where r is the radius of the radius of the circular path on which the car is travelling. As radius r is smaller for a sharper turn, the acceleration called as centripetal or normal acceleration will be more than for a less sharp turn. This is primarily provided by the gravity as you must have seen that the roads having sharper turns are banked heavily than those having small turns.

Answer 3

Err, yeah. Acceleration is metres per second per second (increase in speed every second, m2) - your car is travelling around both corners at a constant 60km/h - this is velocity and not acceleration therefore acceleration is zero in both cases ( km/h is the same as m/s and both used to measure velocity).

Answer 4

The guy who posted ahead of me is correct. Anytime you have a change in direction, you have to have a change in velocity IN that direction.

Say you are going due north. This means your velocity in the east direction is 0. If you slowly start turning east you start to gain velocity in the east direction. Its an easier way of thinking about it I think.

But the easy answer is that when going around a curve, you now have centripetal acceleration.

Answer 5

I don't understand the question, when you say ACCELERATION at a CONSTANT speed,.... you don't have acceleration...at a constant speed, or you'd be speeding up. BUT...if you mean "Sliding"...then yes...the sharper corner is cutting a larger angle away from the inertia of the car, that wants to keep going straight, thus is more apt to skid out, but that also depends on tire friction....hope this helps.

Answer 6

if you asked the question right then there is no acceleration in either case. both are at a constant 60