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I took a chemistry test. There was this one question that ahs been bothering me all week. this question was:

If hydrogen atom goes from energy level n=3 to n=1 what is the number of spectrum line produced(something like that)?

Answers
a. 1
b. 2
c. 3
d. infinity

-I answered c. 3

2006-11-24 09:53:56 · 6 answers · asked by avalentin911 2 in Science & Mathematics Chemistry

6 answers

The correct answer is 3.
The 1st spectral line is caused by the electron falling from state 2 to state1. The 2nd line is caused by a shift from 3 to 2, and the third, a shift from 3 to 1.

2006-11-24 19:39:17 · answer #1 · answered by Helmut 7 · 0 0

Answer is a.1.

When the electron moves from level 3 to 1 energy of the emitted ray is 12.087 eV. The wavelength of the spectrum is 1026 A ('A' for Angstroms) or 102.6 nM (nano-meters) The energy emitted is in the Lyman spectrum.

Remember the Bohr's model ? Energy is emitted in quanta. Each quanta has specific energy levels depending on the wavelength of the spectrum emitted. Remember the Planck’s equation : E = h v, where v (pronounced as new) is the frequency of the electro-magnetic radiation emitted.

This can be rewritten as

E = h * c / l

where 'E' is energy, 'h' is Planck's constant, 'c' is the velocity of light (electro-magnetic radiation) and 'l' is lambda wave length.

Electron from energy level E3 moves to energy level E1 then the energy difference is given as

E3-E1 = dE = h c / l

This means that the energy given out is of one wave length of light (electromagnetic radiation) specific to the quanta of energy emitted.

2006-11-26 13:51:25 · answer #2 · answered by krishash49 2 · 0 0

An electron can bypass to any form of ability stages, or perhaps as it falls decrease go into reverse to a decrease element it supplies off ability as a photon, for this reason an emission line. that's the version in ability stages that defines the frequency of an emission (E=hf), truly than any resources of the electron or form of electrons --------------------------- n=4 -------------o-----o----- n=3 .............|.......| -------------o------------ n=2 .....................| .....................| -------------------o------ n=a million imagine the circles contained in the right line are electrons (contained when it comes to hydrogen this may be 2 separate circumstances) the electron can fall to both the line lower than, or 2 strains lower than, the flexibility hollow is distinct, so the photon given off will also be distinct. In a hydrogen atom electrons falling to n=2 provide emission strains contained in the Balmer sequence, electrons falling to the n=a million provide emission strains contained in the Lyman sequence.

2016-11-29 10:36:45 · answer #3 · answered by Anonymous · 0 0

on my opinion it is 3. as there are only three energy levels in consideration electrons can jump from n=3 to n=2 and n=3 to n=1 then also from n=2to n=1.thus there will be three lines produced from the emitted three different energies.

2015-05-12 18:40:12 · answer #4 · answered by asel 1 · 0 0

I think a.1 because much lighter is possible to this kind of element.

2006-11-24 10:05:02 · answer #5 · answered by ker_vin2006 2 · 0 0

you were right

2006-11-24 09:58:37 · answer #6 · answered by Eat organic stuff 2 · 0 0

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