AHHHHH I CANT FIGURE THIS OUt!?

Question

HELP PLEASE!!!

The bottom of a box is a rectangle witha length of five cm more than the width. the height of the box is four cm and its volume is 264 cm cubed. find the dimensions of the box.

Answer 1

Let the width be x. Then the length is x+5.
So the volume = height*width*length = 4x(x+5).
So you want to solve 4x(x+5) = 264, or equivalently, x(x+5) = 66.
Expanding and putting everything on the left gives:
x^2 + 5x - 66 = 0
We can factorise that:
(x+11)(x-6) = 0
So x = -11 or 6.
-11 isn't really going to be a very good width, so the width is 6, the length is 6+5 = 11, and the height is 4.

Answer 2

Answer: 11x6x4

You are told that V=264 and h=4. Because V=l*w*h, you can conclude that 264=l*w*4. You can then divide each side by 4 giving you 66=l*w. You also know that l = w+5. Therefore, (w+5)*w = 66. Then, you can distribute the w giving you w^2+5w=66. You can then sub the 66 to the left and use the road or whatever method you are taught.

V=lwh
264=4lw
66=lw
66=(w+5)w
66=w^2+5w
0=w^2+5w-66
0=(w-11)(w-6)
w=6,11

Answer 3

Well, a box's volume is its length times its width times its height, so:

264cm cubed= 4 cm X Width X (Width plus 5)

And we divide out the four, and place W in to replace width, giving us:

66 = W X (W+5)

Then we multiply it out, giving us:

66 = W squared + 5W

and we subtract to get

0= W squared + 5W -66

Then we use the quadratic formula to get:

w=(-5 +/- 17) /2

which gives us 6.

so, we get that

width is 6
height is 4
length is 11

Answer 4

11*6*4=264

Answer 5

let width be x cm
then lenght will be 5 + x
h=4cm
V=l*h*w
264=(5+x)(x)(4)
u will get simultaneous eq.
4x^2+20x-264=0
(4x-24)(x+11)=0
x=-11,6
-ive can't be possible therefore 6 is width, length is 11

Answer 6

good luck with that

Answer 7

me no no