how do you do this problem wit y=mx+b?

Question

x+y = 4
2x-y = 2

Answer 1

You don't, really. y = mx + b is the slope-intercept line equation, where m = slope and b = y-intercept (the place where x = 0). I guess you could put both equations in this format, draw the resulting lines, and find where they converge (cross). That would be easy to do on graph paper, but more difficult to show here.

One of the other ways to solve the equation system is to substitute one variable for the other. To do this, you'd first need to put one of the equations in a format where a single variable is by itself on one side of the equation, like this:
y = 2x - 2

Then plug in the value on the right side of that equation instead of y in the first equation:
x + (2x + 2) = 4
3x + 2 = 4
3x = 2
x = 2/3

Then plug that back into one of the equations and solve for y
2/3 + y = 4
y = 10/3

The point of convergence for the system is (2/3, 10/3)

Answer 2

Each number is a straight line vis a vis y = mx+b
Solve them simultaneously and get the value for (x,y) where these two lines cross.
x + y = 4
2x - y = 2
Add them: 3x = 6, so x = 2; now plug x into either equation, I'll use the top one:
2 + y = 4
y = 4 - 2 = 2
I hope this was your question

But if you want to make each equation into the straight line form, then the first one is
y = -x + 4, simply by subtracting x from both sides; the other one is
y = -2x + 2

I hope that between the two explanations above, you get the answer you are looking for.

Answer 3

Solving the equations is pretty easy. x = 2 and y = 2.

Not sure what your question means, but taking a stab at it, I'll assume that you're supposed to put the 2 equations in slope-intercept form (y = mx + b), graph them, and show where the lines cross.

To do that, you would take both equations, arrange them so that only y is on the left of the equal sign. Then the number in front of x is the slope m, aka the "rise over the run", and the other number is b, the y-intercept, which means the value of y where the line crosses the y-axis.

So for example, the first equation would be:

y = -x + 4

So the line crosses the y-axis at y=4, and the slope of the line is -1.

Is that what you're looking for?

Answer 4

Not sure what you are asking

Do you want to put each equation into the y = mx + b form?

x+y = 4
y = -1x + 4

2x-y = 2
-y = -2x + 2
y = 2x - 2


Or do you want to solve the system of equations?

x+y = 4
2x-y = 2
-------------
3x = 6 {add the two equations}
x = 2

x + y = 4
2 + y = 4
y = 2

Check

2x - y = 2
2(2) - 2 = = 2
4 - 2 = 2
2 = 2

Answer 5

Do you have to use y = mx + b?

In this case the easiest way to solve is to add the equations together so the y terms drop out, find x, then sub back in to get x (I think in fact you find they are equal).

If you have to use y = mx + b (?but why???)
the first one is y = -x + 4 ( so it has gradient -1, y intercept 4)
for the second you add y to both sides getting 2x = y+2
and then subtract 2 from both sides getting
y = 2x - 2, [which is not y = x, Andrew, though as it happens y is equal to x at the solution point, so this error would still lead to the correct answer]

Now, comparing both equations, equate the things that y is equal to:
2x - 2 = -x + 4, solve this for x, then put the value you get into either of the equations in the form y = ...

Answer 6

a million) -10x=5y will be switched over into the slope-intercept variety (y=mx+b) the position m is the slope of the instantly line (m=upward thrust/run=y/x) and b because the y-intercept, it truly is a level of intersection of the line and the y-axis. -10x=5y is a similar as y=-10x/5=-2x+0. right here b is 0 and the slope is -2, which ability the line passes by the beginning and leans on the left at a value of two upward thrust to one run. 2) 2x-3y=6 will be solved by a similar answer as above or you should use the intercept-variety. purely divide the consistent 6 by the coefficients of x and y, 2 and -3,respectively, to locate the x and y-intercepts. So the x and y-intercept are 3 and -2. respectively. To graph the line, plot the intercepts (3,0) and (0,-2) on the Cartesian airplane then connect those factors, the line will be prolonged infinitely.

Answer 7

I am a bit confused on the question. Do you want to change the two equations into y=mx+b form? if so,
y=-x+4
y=x
from here, you can see the slope in the first on is -1, and a y-int of 4, in the second one, a slope of 1 and a y int of 0

Answer 8

x+y=4 into y=mx+b
First subtract x from both sides
y = 4 - x
Rewrite:
y= -x + 4 Realize the m in this case is -1

2x - y = 2 into y = mx + b
Add y to both sides
2x = 2 + y
Subract 2 from both sides
2x - 2 = y
Rewrite
y = 2x - 2

Answer 9

x=y/2=2 whats m and b?