my sister has had 3 kids in a row with blue eyes when genetically there only suppose to have a 1 in 4 chance of a blue eyed kid. both are carriers for the blue eyed gene.
2006-11-24 07:30:20 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Biology
probability and how thats even possible
2006-11-24 07:40:02 · update #1
I'm assuming that each parent is Bb which would in fact give you the 1/4 probability.
So, for 3 kids in a row, the probability is 1/4 x 1/4 x 1/4 which is 1/64.
2006-11-24 07:34:13 · answer #1 · answered by Anonymous · 3⤊ 0⤋
You haven't mentioned whether either parent has brown eyes. A person with brown eyes (phenotype) may either have two brown genes (genotype) or a blue and a brown. If each parent has brown eyes, and if each has one brown + one blue genotype, then probability indeed dictates that only 1/4 of their children will have blue eyes. But probability only governs large numbers of samples, not individual cases. If a person tosses a coin 1000 times, six heads in a row is common sometime.
Also, if both parents are blue-eyed, and if both gave two blue genes, then they probably will never have broiwn-eyed children.
2006-11-24 15:47:17 · answer #2 · answered by steve_geo1 7 · 0⤊ 0⤋
1/4 * 1/4 * 1/4 = 1/64
That's not particularly high odds. Just because something is improbable doesn't make it impossible.
2006-11-24 16:10:42 · answer #3 · answered by Stuart 3 · 0⤊ 0⤋
what's the question if i'm right it should be 3/4
2006-11-24 15:39:59 · answer #4 · answered by nnflwr 1 · 0⤊ 0⤋
k
2006-11-24 15:37:19 · answer #5 · answered by Anonymous · 0⤊ 1⤋