I can get this far n!/(n-4)! = 56 [n!/(n-2)!]
then I am stuck.
thank you
2006-11-24 05:03:44 · 5 answers · asked by Jen H 1 in Science & Mathematics ➔ Mathematics
so far, so good
n!/(n-4)! = 56 [n!/(n-2)!]
multiply both sides by (n-2)!/n!
[n!(n-2)!] / [n!(n-4)!] = 56
(n-2)! / (n-4)! = 56
(n-2)(n-3) = 56
You could multiply this out and solve the quadratic, in which case you will get one positive and one negative root, or if you remember that 56 = 8*7, then that quickly leads to n = 10
2006-11-24 05:06:59 · answer #1 · answered by Scott R 6 · 2⤊ 1⤋
basically when I know it as a difficulty do I initiate the activity. Many a situations I basically smile at it sweetly as is my nature each and every time I confront all of us, even say hi. i'm so dumb. Its basically while as a substitute of greeting me returned it shows a glum face or sock me that I understand its confrontational temper. Then on I plan to get even....or basically sleep over it.
2016-12-10 15:06:10 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Cancel n! and (n-4)!
So, (n-3)(n-2) = 56
Thus n=10
2006-11-24 05:16:53 · answer #3 · answered by ag_iitkgp 7 · 1⤊ 1⤋
(n-2)!=(n-2)(n-3)(n-4)!
2006-11-24 05:07:56 · answer #4 · answered by raj 7 · 1⤊ 1⤋
sorry...... i hate math!!!!!!!!!
2006-11-24 05:05:31 · answer #5 · answered by Anonymous · 1⤊ 4⤋